AEC-Multi-Weight多权重


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流程图


原始矩阵如下:


$$ \begin{array}{c|c|c|c|c|c|c}{M_{11 \times15}} & -PN1 & -PN2 & -PE1 & -PS1 & -PS2 &SN1 &SN2 &SN3 &SE1 &SS1 &RN1 &RN2 &RE1 &RE2 &RS1\\ \hline 2011 &0.654302103 &278.5577711 &0.104246565 &426.623418 &0.484969128 &0.518335321 &0.734225621 &0.050682504 &8.714200492 &8.950944846 &0.850812256 &10.3 &7380.279843 &35115.65191 &176.2\\ \hline 2012 &0.64018787 &230.2072698 &0.100574919 &430.0655108 &0.498760764 &0.524293616 &0.720190933 &0.053800771 &8.311141515 &8.547470721 &0.868804512 &11.1 &8725.395288 &39690.62085 &170.1\\ \hline 2013 &0.634839501 &232.7438152 &0.095228796 &433.091812 &0.510793577 &0.534174192 &0.725746269 &0.053359371 &8.162741259 &8.838568347 &0.889545989 &12.82 &10872.14779 &43857.04467 &144.4\\ \hline 2014 &0.621034465 &198.6498147 &0.094446274 &435.3089733 &0.524130018 &0.545060211 &0.730176133 &0.05345935 &8.324123649 &10.36566358 &0.912120266 &8.67 &12075.052 &47967.53527 &159.4\\ \hline 2015 &0.617366121 &179.1637029 &0.093725645 &438.6801925 &0.540016156 &0.547408526 &0.727055177 &0.052997358 &8.456326593 &10.10966409 &0.932741508 &50.29 &13182.83334 &51652.87565 &157.2\\ \hline 2016 &0.614656439 &134.5724311 &0.093564023 &442.1742592 &0.558923488 &0.547604836 &0.732802092 &0.052527861 &8.333882334 &10.73475734 &0.951164027 &50.54 &14328.14133 &55939.46599 &138.94\\ \hline 2017 &0.605388917 &93.61972547 &0.086820781 &445.1131496 &0.577785857 &0.548797995 &0.737336045 &0.052199574 &8.053402438 &11.01950072 &0.958207523 &62.2 &15557.73277 &61583.50207 &252.86\\ \hline st1 &0.4 &100 &0.05 &400 &0.3 &0.7 &0.8 &0.1 &10 &20 &0.95 &12 &30000 &50000 &150\\ \hline st2 &0.6 &200 &0.1 &600 &0.5 &0.5 &0.7 &0.08 &8 &15 &0.9 &9 &20000 &40000 &100\\ \hline st3 &0.7 &300 &0.2 &800 &0.6 &0.4 &0.6 &0.05 &6 &10 &0.8 &6 &15000 &30000 &50\\ \hline st4 &0.8 &400 &0.3 &1000 &0.7 &0.3 &0.5 &0.02 &4 &5 &0.7 &3 &10000 &20000 &20\\ \hline \end{array} $$


采用的归一方法如下


极差法

正向指标公式:$$ n_{ij} = \frac{{o_{ij}-min(o_{j})}}{{max(o_{j})-min(o_{j})}} $$

负向指标公式:$$ n_{ij} = \frac{max(o_{j})-{o_{ij}}}{{max(o_{j})-min(o_{j})}} $$


归一化矩阵如下


$$ \begin{array}{c|c|c|c|c|c|c}{M_{11 \times15}} & -PN1 & -PN2 & -PE1 & -PS1 & -PS2 &SN1 &SN2 &SN3 &SE1 &SS1 &RN1 &RN2 &RE1 &RE2 &RS1\\ \hline 2011 &0.364 &0.396 &0.783 &0.956 &0.538 &0.546 &0.781 &0.384 &0.786 &0.263 &0.584 &0.123 &0 &0.364 &0.671\\ \hline 2012 &0.4 &0.554 &0.798 &0.95 &0.503 &0.561 &0.734 &0.423 &0.719 &0.236 &0.654 &0.137 &0.059 &0.474 &0.645\\ \hline 2013 &0.413 &0.546 &0.819 &0.945 &0.473 &0.585 &0.752 &0.417 &0.694 &0.256 &0.734 &0.166 &0.154 &0.574 &0.534\\ \hline 2014 &0.447 &0.657 &0.822 &0.941 &0.44 &0.613 &0.767 &0.418 &0.721 &0.358 &0.822 &0.096 &0.208 &0.673 &0.599\\ \hline 2015 &0.457 &0.721 &0.825 &0.936 &0.4 &0.619 &0.757 &0.412 &0.743 &0.341 &0.901 &0.799 &0.257 &0.761 &0.589\\ \hline 2016 &0.463 &0.866 &0.826 &0.93 &0.353 &0.619 &0.776 &0.407 &0.722 &0.382 &0.973 &0.803 &0.307 &0.864 &0.511\\ \hline 2017 &0.487 &1 &0.853 &0.925 &0.306 &0.622 &0.791 &0.402 &0.676 &0.401 &1 &1 &0.362 &1 &1\\ \hline st1 &1 &0.979 &1 &1 &1 &1 &1 &1 &1 &1 &0.968 &0.152 &1 &0.721 &0.558\\ \hline st2 &0.5 &0.653 &0.8 &0.667 &0.5 &0.5 &0.667 &0.75 &0.667 &0.667 &0.775 &0.101 &0.558 &0.481 &0.344\\ \hline st3 &0.25 &0.326 &0.4 &0.333 &0.25 &0.25 &0.333 &0.375 &0.333 &0.333 &0.387 &0.051 &0.337 &0.24 &0.129\\ \hline st4 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0.116 &0 &0\\ \hline \end{array} $$

正极值点构成
$$ \begin{array}{c|c|c|c|c|c|c}{M_{1 \times15}} & -PN1 & -PN2 & -PE1 & -PS1 & -PS2 &SN1 &SN2 &SN3 &SE1 &SS1 &RN1 &RN2 &RE1 &RE2 &RS1\\ \hline \mathbf{Zone^+} &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1\\ \hline \end{array} $$
负极值点构成
$$ \begin{array}{c|c|c|c|c|c|c}{M_{1 \times15}} & -PN1 & -PN2 & -PE1 & -PS1 & -PS2 &SN1 &SN2 &SN3 &SE1 &SS1 &RN1 &RN2 &RE1 &RE2 &RS1\\ \hline \mathbf{Zone^-} &0 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0 &0\\ \hline \end{array} $$

采用的是熵权法(EWM)求权重


$$ \begin{array}{c|c|c|c|c|c|c}{M_{2 \times15}} & -PN1 & -PN2 & -PE1 & -PS1 & -PS2 &SN1 &SN2 &SN3 &SE1 &SS1 &RN1 &RN2 &RE1 &RE2 &RS1\\ \hline EWM所得权重 &0.0563 &0.0522 &0.04 &0.0445 &0.0592 &0.0486 &0.0425 &0.0565 &0.0426 &0.0742 &0.0444 &0.1965 &0.1234 &0.0573 &0.0619\\ \hline 权重大小顺序 &8 &9 &15 &11 &5 &10 &14 &7 &13 &3 &12 &1 &2 &6 &4\\ \hline \end{array} $$

VIKOR的最大化群体效益和最小化反对意见的个别遗憾


最大化群体效益
最小化反对意见的个别遗憾
$$ S_i = \sum_\limits{j=1}^m{ \omega_{j} \left(\frac{Zone_j^+ -n_{ij}}{Zone_j^+ -Zone_j^-} \right)} \quad \quad $$ $$ R_i = \max_\limits{j=1} { \left( \omega_{j} (\frac{Zone_j^+ -n_{ij}}{Zone_j^+ -Zone_j^-} )\right)} \quad \quad $$

代入权重值等即得(S R)两列矩阵,两列都为负向指标


$$ \begin{array}{c|c|c|c|c|c|c}{M_{11 \times2}} &期望值 &遗憾值\\ \hline 2011 &0.6067 &0.1724\\ \hline 2012 &0.5845 &0.1697\\ \hline 2013 &0.5633 &0.164\\ \hline 2014 &0.5405 &0.1778\\ \hline 2015 &0.3876 &0.0918\\ \hline 2016 &0.3686 &0.0856\\ \hline 2017 &0.2775 &0.0789\\ \hline st1 &0.2126 &0.1668\\ \hline st2 &0.5022 &0.1767\\ \hline st3 &0.7471 &0.1867\\ \hline st4 &0.9858 &0.1965\\ \hline \end{array} $$

妥协解的公式


公式
$$ Q_i = \left( 1-k \right) \left(\frac{S_i - Min(S_i)}{Max(S_i) -Min(S_i)} \right) + k\left(\frac{R_i - Min(R_i)}{Max(R_i) -Min(R_i)} \right) $$

截距方式分析k的值——也是常规方法


一般的论文对于下面的公式

$$ Q_i = \left( 1-k \right) \left(\frac{S_i - Min(S_i)}{Max(S_i) -Min(S_i)} \right) + k\left(\frac{R_i - Min(R_i)}{Max(R_i) -Min(R_i)} \right) $$

其中的$k$随便说一下取0.5就拉倒了。这个好比小学生的四舍五入一样天经地义。事实上这个值很有得商榷的。它是一个敏感性有强有弱的范围。

$$ 对于每一行 令a_i =\frac{S_i - Min(S_i)}{Max(S_i) -Min(S_i)} \quad \quad b_i =\frac{R_i - Min(R_i)}{Max(R_i) -Min(R_i)} $$

$$ Q_i = \left( 1-k \right) a_i + kb_i \quad \quad $$

对于 $x,y$样本

$$ \begin{cases} \left( 1-k \right) a_x + kb_x \\ \left( 1-k \right) a_y + kb_y \end{cases} $$

以上问题就变成了求两条线段是否在$[0,1]$值域内有相交的问题,此题属于初中的知识范畴,不再详细描述。

$$ \left( 1-k \right) a_x + kb_x =\left( 1-k \right) a_y + kb_y $$

$$ a_x-k a_x + kb_x =a_y-k a_y + kb_y $$

$$ a_x- a_y=-k a_y + kb_y +k a_x - kb_x $$

$$ a_x- a_y=(- a_y + b_y + a_x - b_x)k $$

$$ k =\frac{a_x- a_y}{( a_x- a_y + b_y - b_x)} $$


基础矩阵如下


$$Base=\begin{array}{c|c|c|c|c|c|c}{M_{11 \times2}} &a_i &b_i\\ \hline 2011 &0.5097 &0.7954\\ \hline 2012 &0.4809 &0.7728\\ \hline 2013 &0.4536 &0.7242\\ \hline 2014 &0.4241 &0.8415\\ \hline 2015 &0.2264 &0.1103\\ \hline 2016 &0.2018 &0.0571\\ \hline 2017 &0.084 &0\\ \hline st1 &0 &0.7474\\ \hline st2 &0.3745 &0.8322\\ \hline st3 &0.6913 &0.9169\\ \hline st4 &1 &1\\ \hline \end{array} $$

拐点k值分析


$$Qk_{matrix}=\begin{array}{c|c|c|c|c|c|c}{M_{11 \times12}} &k=0 &k=0.101 &k=0.201 &k=0.226 &k=0.262 &k=0.423 &k=0.453 &k=0.642 &k=0.65 &k=0.786 &k=0.951 &k=1\\ \hline 2011 &0.51 &0.539 &0.567 &0.574 &0.585 &0.631 &0.639 &0.693 &0.696 &0.734 &0.782 &0.795\\ \hline 2012 &0.481 &0.51 &0.54 &0.547 &0.557 &0.604 &0.613 &0.668 &0.671 &0.71 &0.759 &0.773\\ \hline 2013 &0.454 &0.481 &0.508 &0.515 &0.525 &0.568 &0.576 &0.627 &0.63 &0.666 &0.711 &0.724\\ \hline 2014 &0.424 &0.466 &0.508 &0.519 &0.534 &0.601 &0.613 &0.692 &0.696 &0.752 &0.821 &0.841\\ \hline 2015 &0.226 &0.215 &0.203 &0.2 &0.196 &0.177 &0.174 &0.152 &0.151 &0.135 &0.116 &0.11\\ \hline 2016 &0.202 &0.187 &0.173 &0.169 &0.164 &0.141 &0.136 &0.109 &0.108 &0.088 &0.064 &0.057\\ \hline 2017 &0.084 &0.076 &0.067 &0.065 &0.062 &0.048 &0.046 &0.03 &0.029 &0.018 &0.004 &0\\ \hline st1 &0 &0.076 &0.15 &0.169 &0.196 &0.316 &0.339 &0.48 &0.486 &0.588 &0.711 &0.747\\ \hline st2 &0.375 &0.421 &0.466 &0.478 &0.494 &0.568 &0.582 &0.668 &0.672 &0.734 &0.81 &0.832\\ \hline st3 &0.691 &0.714 &0.737 &0.742 &0.75 &0.787 &0.793 &0.836 &0.838 &0.869 &0.906 &0.917\\ \hline st4 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1\\ \hline \end{array} $$

排序分析


上述是负向指标,数值越小越好,每一列数值最小的排第一。因此排序情况如下:

$$Q_{rank}=\begin{array}{c|c|c|c|c|c|c}{M_{11 \times12}} &k=0 &k=0.101 &k=0.201 &k=0.226 &k=0.262 &k=0.423 &k=0.453 &k=0.642 &k=0.65 &k=0.786 &k=0.951 &k=1\\ \hline 2011 &9 &9 &9 &9 &9 &9 &9 &9 &8 &7 &7 &7\\ \hline 2012 &8 &8 &8 &8 &8 &8 &7 &6 &6 &6 &6 &6\\ \hline 2013 &7 &7 &6 &6 &6 &5 &5 &5 &5 &5 &4 &4\\ \hline 2014 &6 &6 &6 &7 &7 &7 &7 &8 &8 &9 &9 &9\\ \hline 2015 &4 &4 &4 &4 &3 &3 &3 &3 &3 &3 &3 &3\\ \hline 2016 &3 &3 &3 &2 &2 &2 &2 &2 &2 &2 &2 &2\\ \hline 2017 &2 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1\\ \hline st1 &1 &1 &2 &2 &3 &4 &4 &4 &4 &4 &4 &5\\ \hline st2 &5 &5 &5 &5 &5 &5 &6 &6 &7 &7 &8 &8\\ \hline st3 &10 &10 &10 &10 &10 &10 &10 &10 &10 &10 &10 &10\\ \hline st4 &11 &11 &11 &11 &11 &11 &11 &11 &11 &11 &11 &11\\ \hline \end{array} $$


聚类特征


序号 聚类特征-对应k值区段 Q值排序
10<$k$< 0.101067$st1 \succ 2017 \succ 2016 \succ 2015 \succ st2 \succ 2014 \succ 2013 \succ 2012 \succ 2011 \succ st3 \succ st4$
20.101067<$k$< 0.200967$2017 \succ st1 \succ 2016 \succ 2015 \succ st2 \succ 2014 \succ 2013 \succ 2012 \succ 2011 \succ st3 \succ st4$
30.200967<$k$< 0.226209$2017 \succ st1 \succ 2016 \succ 2015 \succ st2 \succ 2013 \succ 2014 \succ 2012 \succ 2011 \succ st3 \succ st4$
40.226209<$k$< 0.262163$2017 \succ 2016 \succ st1 \succ 2015 \succ st2 \succ 2013 \succ 2014 \succ 2012 \succ 2011 \succ st3 \succ st4$
50.262163<$k$< 0.422854$2017 \succ 2016 \succ 2015 \succ st1 \succ st2 \succ 2013 \succ 2014 \succ 2012 \succ 2011 \succ st3 \succ st4$
60.422854<$k$< 0.45294$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ st2 \succ 2014 \succ 2012 \succ 2011 \succ st3 \succ st4$
70.45294<$k$< 0.642061$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ st2 \succ 2012 \succ 2014 \succ 2011 \succ st3 \succ st4$
80.642061<$k$< 0.650297$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ 2012 \succ st2 \succ 2014 \succ 2011 \succ st3 \succ st4$
90.650297<$k$< 0.786398$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ 2012 \succ st2 \succ 2011 \succ 2014 \succ st3 \succ st4$
100.786398<$k$< 0.951409$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ 2012 \succ 2011 \succ st2 \succ 2014 \succ st3 \succ st4$
110.951409<$k$< 1$2017 \succ 2016 \succ 2015 \succ 2013 \succ st1 \succ 2012 \succ 2011 \succ st2 \succ 2014 \succ st3 \succ st4$

聚类特征



第二种权重方式


采用的CRITIC方法求权重


$$ \begin{array}{c|c|c|c|c|c|c}{M_{2 \times15}} & -PN1 & -PN2 & -PE1 & -PS1 & -PS2 &SN1 &SN2 &SN3 &SE1 &SS1 &RN1 &RN2 &RE1 &RE2 &RS1\\ \hline CRITIC方法所得权重 &0.0532 &0.0668 &0.0663 &0.0779 &0.0587 &0.06 &0.0658 &0.0601 &0.0637 &0.0626 &0.0728 &0.0884 &0.0677 &0.0701 &0.0659\\ \hline 权重大小顺序 &15 &6 &7 &2 &14 &13 &9 &12 &10 &11 &3 &1 &5 &4 &8\\ \hline \end{array} $$

代入权重值等即得(S R)两列矩阵,两列都为负向指标


$$ \begin{array}{c|c|c|c|c|c|c}{M_{11 \times2}} &期望值 &遗憾值\\ \hline 2011 &0.4998 &0.0775\\ \hline 2012 &0.4785 &0.0763\\ \hline 2013 &0.4624 &0.0738\\ \hline 2014 &0.4294 &0.08\\ \hline 2015 &0.3507 &0.0504\\ \hline 2016 &0.3304 &0.0469\\ \hline 2017 &0.2576 &0.0432\\ \hline st1 &0.1274 &0.075\\ \hline st2 &0.4332 &0.0795\\ \hline st3 &0.716 &0.084\\ \hline st4 &0.9922 &0.0884\\ \hline \end{array} $$$$Base=\begin{array}{c|c|c|c|c|c|c}{M_{11 \times2}} &a_i &b_i\\ \hline 2011 &0.4306 &0.7602\\ \hline 2012 &0.4059 &0.7337\\ \hline 2013 &0.3874 &0.6768\\ \hline 2014 &0.3492 &0.8142\\ \hline 2015 &0.2582 &0.1576\\ \hline 2016 &0.2348 &0.0816\\ \hline 2017 &0.1506 &0\\ \hline st1 &0 &0.7039\\ \hline st2 &0.3537 &0.8033\\ \hline st3 &0.6806 &0.9026\\ \hline st4 &1 &1\\ \hline \end{array} $$

拐点k值分析


$$Qk_{matrix}=\begin{array}{c|c|c|c|c|c|c}{M_{11 \times13}} &k=0 &k=0.176 &k=0.21 &k=0.217 &k=0.274 &k=0.288 &k=0.321 &k=0.413 &k=0.429 &k=0.601 &k=0.641 &k=0.934 &k=1\\ \hline 2011 &0.431 &0.489 &0.5 &0.502 &0.521 &0.526 &0.536 &0.567 &0.572 &0.629 &0.642 &0.739 &0.76\\ \hline 2012 &0.406 &0.464 &0.475 &0.477 &0.496 &0.5 &0.511 &0.541 &0.547 &0.603 &0.616 &0.712 &0.734\\ \hline 2013 &0.387 &0.438 &0.448 &0.45 &0.467 &0.471 &0.48 &0.507 &0.512 &0.561 &0.573 &0.658 &0.677\\ \hline 2014 &0.349 &0.431 &0.447 &0.45 &0.477 &0.483 &0.498 &0.541 &0.549 &0.629 &0.647 &0.784 &0.814\\ \hline 2015 &0.258 &0.24 &0.237 &0.236 &0.231 &0.229 &0.226 &0.217 &0.215 &0.198 &0.194 &0.164 &0.158\\ \hline 2016 &0.235 &0.208 &0.203 &0.202 &0.193 &0.191 &0.186 &0.171 &0.169 &0.143 &0.137 &0.092 &0.082\\ \hline 2017 &0.151 &0.124 &0.119 &0.118 &0.109 &0.107 &0.102 &0.088 &0.086 &0.06 &0.054 &0.01 &0\\ \hline st1 &0 &0.124 &0.148 &0.153 &0.193 &0.203 &0.226 &0.291 &0.302 &0.423 &0.451 &0.658 &0.704\\ \hline st2 &0.354 &0.433 &0.448 &0.451 &0.477 &0.483 &0.498 &0.539 &0.547 &0.624 &0.642 &0.774 &0.803\\ \hline st3 &0.681 &0.72 &0.727 &0.729 &0.741 &0.745 &0.752 &0.772 &0.776 &0.814 &0.823 &0.888 &0.903\\ \hline st4 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1\\ \hline \end{array} $$

排序分析


上述是负向指标,数值越小越好,每一列数值最小的排第一。因此排序情况如下:

$$Q_{rank}=\begin{array}{c|c|c|c|c|c|c}{M_{11 \times13}} &k=0 &k=0.176 &k=0.21 &k=0.217 &k=0.274 &k=0.288 &k=0.321 &k=0.413 &k=0.429 &k=0.601 &k=0.641 &k=0.934 &k=1\\ \hline 2011 &9 &9 &9 &9 &9 &9 &9 &9 &9 &8 &7 &7 &7\\ \hline 2012 &8 &8 &8 &8 &8 &8 &8 &7 &6 &6 &6 &6 &6\\ \hline 2013 &7 &7 &6 &5 &5 &5 &5 &5 &5 &5 &5 &4 &4\\ \hline 2014 &5 &5 &5 &5 &6 &6 &7 &7 &8 &8 &9 &9 &9\\ \hline 2015 &4 &4 &4 &4 &4 &4 &3 &3 &3 &3 &3 &3 &3\\ \hline 2016 &3 &3 &3 &3 &2 &2 &2 &2 &2 &2 &2 &2 &2\\ \hline 2017 &2 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1 &1\\ \hline st1 &1 &1 &2 &2 &2 &3 &3 &4 &4 &4 &4 &4 &5\\ \hline st2 &6 &6 &6 &7 &7 &6 &6 &6 &6 &7 &7 &8 &8\\ \hline st3 &10 &10 &10 &10 &10 &10 &10 &10 &10 &10 &10 &10 &10\\ \hline st4 &11 &11 &11 &11 &11 &11 &11 &11 &11 &11 &11 &11 &11\\ \hline \end{array} $$


聚类特征


序号 聚类特征-对应k值区段 Q值排序
10<$k$< 0.17622$st1 \succ 2017 \succ 2016 \succ 2015 \succ 2014 \succ st2 \succ 2013 \succ 2012 \succ 2011 \succ st3 \succ st4$
20.17622<$k$< 0.210479$2017 \succ st1 \succ 2016 \succ 2015 \succ 2014 \succ st2 \succ 2013 \succ 2012 \succ 2011 \succ st3 \succ st4$
30.210479<$k$< 0.217247$2017 \succ st1 \succ 2016 \succ 2015 \succ 2014 \succ 2013 \succ st2 \succ 2012 \succ 2011 \succ st3 \succ st4$
40.217247<$k$< 0.273938$2017 \succ st1 \succ 2016 \succ 2015 \succ 2013 \succ 2014 \succ st2 \succ 2012 \succ 2011 \succ st3 \succ st4$
50.273938<$k$< 0.28791$2017 \succ 2016 \succ st1 \succ 2015 \succ 2013 \succ 2014 \succ st2 \succ 2012 \succ 2011 \succ st3 \succ st4$
60.28791<$k$< 0.320938$2017 \succ 2016 \succ st1 \succ 2015 \succ 2013 \succ st2 \succ 2014 \succ 2012 \succ 2011 \succ st3 \succ st4$
70.320938<$k$< 0.413326$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ st2 \succ 2014 \succ 2012 \succ 2011 \succ st3 \succ st4$
80.413326<$k$< 0.429126$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ st2 \succ 2012 \succ 2014 \succ 2011 \succ st3 \succ st4$
90.429126<$k$< 0.601276$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ 2012 \succ st2 \succ 2014 \succ 2011 \succ st3 \succ st4$
100.601276<$k$< 0.641342$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ 2012 \succ st2 \succ 2011 \succ 2014 \succ st3 \succ st4$
110.641342<$k$< 0.934492$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ 2012 \succ 2011 \succ st2 \succ 2014 \succ st3 \succ st4$
120.934492<$k$< 1$2017 \succ 2016 \succ 2015 \succ 2013 \succ st1 \succ 2012 \succ 2011 \succ st2 \succ 2014 \succ st3 \succ st4$

AEC求解过程


第一个权重其占比


排名 要素所占区段
02017=0.898933   st1=0.101067   
12016=0.773791   st1=0.125142   2017=0.101067   
22015=0.737837   2016=0.226209   st1=0.035954   
3st1=0.689246   2015=0.262163   2013=0.048591   
42013=0.528555   st2=0.422854   st1=0.048591   
52012=0.357939   2013=0.221887   st2=0.219207   2014=0.200967   
62014=0.251973   2011=0.213602   2013=0.200967   2012=0.189121   st2=0.144337   
72012=0.45294   st2=0.213602   2014=0.197357   2011=0.136101   
82011=0.650297   2014=0.349703   
9st3=1   
10st4=1   

第2个权重其占比


排名 要素所占区段
0st1=0.17622   2017=0.82378   
12017=0.17622   st1=0.097718   2016=0.726062   
22016=0.273938   st1=0.047   2015=0.679062   
32015=0.320938   st1=0.613554   2013=0.065508   
42014=0.217247   2013=0.717245   st1=0.065508   
5st2=0.351695   2013=0.006768   2014=0.070663   2012=0.570874   
62013=0.210479   st2=0.289647   2014=0.125416   2012=0.0158   2011=0.358658   
72012=0.413326   2014=0.18795   2011=0.040066   st2=0.358658   
82011=0.601276   2014=0.398724   
9st3=1   
10st4=1   

合并两个聚类情况(按照等比的比例)


排名 要素所占区段
02017=1.64756   st1=0.35244   
12016=1.452124   2017=0.35244   st1=0.195436   
22015=1.358124   2016=0.547876   st1=0.094   
3st1=1.227108   2015=0.641876   2013=0.131016   
42013=1.43449   2014=0.434494   st1=0.131016   
52012=1.141748   st2=0.70339   2014=0.141326   2013=0.013536   
62011=0.717316   st2=0.579294   2013=0.420958   2014=0.250832   2012=0.0316   
72012=0.826652   st2=0.717316   2014=0.3759   2011=0.080132   
82011=1.202552   2014=0.797448   
9st3=2   
10st4=2   
排名 最优妥协解
优胜情境$2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ 2012 \succ st2 \succ 2014 \succ 2011 \succ st3 \succ st4$
劣汰情境 $2017 \succ 2016 \succ 2015 \succ st1 \succ 2013 \succ 2012 \succ st2 \succ 2014 \succ 2011 \succ st3 \succ st4$

扯蛋模型