解释结构模型快速排序层级分析
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第一步:生成自乘矩阵
系统的邻接矩阵的表示
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第二步:对系统进行环路分析,并获得一个获得一个新序
0=>庚
1=>甲
2=>乙
3=>丙
4=>丁
5=>坎
6=>乾
7=>离
8=>丑
9=>艮
10=>戊
11=>子
12=>壬
13=>己
14=>巽
15=>癸
16=>辛
17=>坤
18=>震
19=>兑
第三步:根据环路与新序,进行矩阵缩减
分析的矩阵为:
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庚 | 甲 | 乙 | 丙 | 丁 | 坎 | 乾 | 离 | 丑 | 艮 | 戊 | 子 | 壬 | 己 | 巽 | 癸 | 辛 | 坤 | 震 | 兑 |
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庚、坎、 |
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乾、 |
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甲、乙、 |
| 艮 |
离、丑、 |
| 戊 |
艮、 |
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乙、 |
| 壬 |
子、 |
| 己 |
戊、壬、 |
| 巽 |
戊、 |
| 癸 |
巽、 |
| 辛 |
癸、 |
| 震 |
庚、壬、 |
| 兑 |
震、 |
第四步:对无环矩阵进行缩边,也就是去掉所有的向前边!
可达矩阵:
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骨架矩阵
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| 甲 |
庚、 |
| 丁 |
丙、 |
| 乾 |
庚、坎、 |
| 离 |
乾、 |
| 丑 |
甲、乙、 |
| 艮 |
离、丑、 |
| 戊 |
艮、 |
| 子 |
乙、 |
| 壬 |
子、 |
| 己 |
戊、壬、 |
| 巽 |
戊、 |
| 癸 |
巽、 |
| 辛 |
癸、 |
| 震 |
庚、壬、 |
| 兑 |
震、 |
第五步:对一般性骨架矩阵进行层级分解,可以是原因优先,可以是结果优先
原因优先层级划分最终图形
结果优先层级划分最终图形
弹性势能最大,两端发散的的层级结果
弹性势能最小,中间靠拢的结果
第六步:对一般性骨架矩阵的中的活动要素进行分析
| 层级的序号 | 原因优先的方法-得到的各层级的要素 | 结果优先的方法-得到的各层级要素 | 共同有的要素 | 活动的要素 |
| 1 | 庚,坎 | 庚,乙,丙,坎,坤 | 庚,坎 | 乙,丙,坤 |
| 2 | 甲,乙,乾 | 甲,丁,乾,子 | 甲,乾 | 乙,丁,子 |
| 3 | 离,丑 | 离,丑,壬 | 离,丑 | 壬 |
| 4 | 艮 | 艮,震 | 艮 | 震 |
| 5 | 戊,子 | 戊,兑 | 戊 | 子,兑 |
| 6 | 壬,巽 | 己,巽 | 巽 | 壬,己 |
| 7 | 丙,癸,震 | 癸 | 癸 | 丙,震 |
| 8 | 丁,己,辛,坤,兑 | 辛 | 辛 | 丁,己,坤,兑 |
由上表计算得出活动的要素以及它们活动的层级:
| 要素的序号 | 要素的名称 | 要素的标题 | 开始层级 | 终止层级 |
| 2 | 乙 | 乙 | 1 | 2 |
| 3 | 丙 | 丙 | 1 | 7 |
| 17 | 坤 | 坤 | 1 | 8 |
| 4 | 丁 | 丁 | 2 | 8 |
| 11 | 子 | 子 | 2 | 5 |
| 12 | 壬 | 壬 | 3 | 6 |
| 18 | 震 | 震 | 4 | 7 |
| 19 | 兑 | 兑 | 5 | 8 |
| 13 | 己 | 己 | 6 | 8 |
找到活动要素,并在层级中移动这些活动要素找出最好的结果。活动的要素要注意本身有因果关系的
A、分层的结果一定要符合箭头一定向上
B、不能增加层级的数目
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