解释结构模型快速排序层级分析
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子 | 丑 | 寅 | 卯 | 辰 | 巳 | 午 | 未 | 申 | 酉 | 戌 | 亥 | 乾 | 坤 | 震 | 巽 | 坎 | 离 | 艮 | 兑 |
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第一步:生成自乘矩阵
系统的邻接矩阵的表示
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子 | 丑 | 寅 | 卯 | 辰 | 巳 | 午 | 未 | 申 | 酉 | 戌 | 亥 | 乾 | 坤 | 震 | 巽 | 坎 | 离 | 艮 | 兑 |
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第二步:对系统进行环路分析,并获得一个获得一个新序
0=>子
1=>坎
2=>丑+乾+巽
3=>寅
4=>震
5=>艮
6=>卯
7=>未
8=>戌
9=>辰
10=>巳
11=>午
12=>申
13=>酉
14=>亥
15=>坤
16=>离
17=>兑
第三步:根据环路与新序,进行矩阵缩减
分析的矩阵为:
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子 | 坎 | 丑+乾+巽 | 寅 | 震 | 艮 | 卯 | 未 | 戌 | 辰 | 巳 | 午 | 申 | 酉 | 亥 | 坤 | 离 | 兑 |
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| 丑+乾+巽 |
子、坎、丑+乾+巽、 |
| 艮 |
震、 |
| 卯 |
艮、 |
| 戌 |
寅、 |
| 辰 |
丑+乾+巽、未、戌、 |
| 巳 |
子、坎、未、 |
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丑+乾+巽、卯、 |
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辰、 |
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卯、 |
| 坤 |
坎、震、 |
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申、 |
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坎、 |
第四步:对无环矩阵进行缩边,也就是去掉所有的向前边!
可达矩阵:
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子 | 坎 | 丑+乾+巽 | 寅 | 震 | 艮 | 卯 | 未 | 戌 | 辰 | 巳 | 午 | 申 | 酉 | 亥 | 坤 | 离 | 兑 |
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骨架矩阵
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子 | 坎 | 丑+乾+巽 | 寅 | 震 | 艮 | 卯 | 未 | 戌 | 辰 | 巳 | 午 | 申 | 酉 | 亥 | 坤 | 离 | 兑 |
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丑 乾 巽 |
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| 丑+乾+巽 |
子、坎、 |
| 艮 |
震、 |
| 卯 |
艮、 |
| 戌 |
寅、 |
| 辰 |
丑+乾+巽、未、戌、 |
| 巳 |
子、坎、未、 |
| 午 |
丑+乾+巽、卯、 |
| 申 |
辰、 |
| 酉 |
卯、 |
| 坤 |
坎、震、 |
| 离 |
申、 |
| 兑 |
坎、 |
第五步:对一般性骨架矩阵进行层级分解,可以是原因优先,可以是结果优先
原因优先层级划分最终图形
结果优先层级划分最终图形
弹性势能最大,两端发散的的层级结果
弹性势能最小,中间靠拢的结果
第六步:对一般性骨架矩阵的中的活动要素进行分析
| 层级的序号 | 原因优先的方法-得到的各层级的要素 | 结果优先的方法-得到的各层级要素 | 共同有的要素 | 活动的要素 |
| 1 | 子,坎,寅 | 子,坎,寅,震,未,亥 | 子,坎,寅 | 震,未,亥 |
| 2 | 丑+乾+巽,震,未,戌 | 丑+乾+巽,艮,戌,巳,坤,兑 | 丑+乾+巽,戌 | 震,未,艮,巳,坤,兑 |
| 3 | 艮,辰 | 卯,辰 | 辰 | 艮,卯 |
| 4 | 卯,申 | 午,申,酉 | 申 | 卯,午,酉 |
| 5 | 巳,午,酉,亥,坤,离,兑 | 离 | 离 | 巳,午,酉,亥,坤,兑 |
由上表计算得出活动的要素以及它们活动的层级:
| 要素的序号 | 要素的名称 | 要素的标题 | 开始层级 | 终止层级 |
| 4 | 震 | 震 | 1 | 2 |
| 7 | 未 | 未 | 1 | 2 |
| 14 | 亥 | 亥 | 1 | 5 |
| 5 | 艮 | 艮 | 2 | 3 |
| 10 | 巳 | 巳 | 2 | 5 |
| 15 | 坤 | 坤 | 2 | 5 |
| 17 | 兑 | 兑 | 2 | 5 |
| 6 | 卯 | 卯 | 3 | 4 |
| 11 | 午 | 午 | 4 | 5 |
| 13 | 酉 | 酉 | 4 | 5 |
找到活动要素,并在层级中移动这些活动要素找出最好的结果。活动的要素要注意本身有因果关系的
A、分层的结果一定要符合箭头一定向上
B、不能增加层级的数目
这个方法很土鳖的,赶紧输入原始矩阵,赶紧看,3秒钟后跳转到更好的方法的页面!
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解释结构模型
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