解释结构模型快速排序层级分析
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子 | 丑 | 寅 | 卯 | 辰 | 巳 | 午 | 未 | 申 | 酉 | 戌 | 亥 | 乾 | 坤 | 震 | 巽 | 坎 | 离 | 艮 | 兑 |
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第一步:生成自乘矩阵
系统的邻接矩阵的表示
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子 | 丑 | 寅 | 卯 | 辰 | 巳 | 午 | 未 | 申 | 酉 | 戌 | 亥 | 乾 | 坤 | 震 | 巽 | 坎 | 离 | 艮 | 兑 |
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第二步:对系统进行环路分析,并获得一个获得一个新序
0=>震
1=>亥
2=>卯
3=>戌
4=>辰+兑
5=>酉
6=>巽
7=>子
8=>丑
9=>午
10=>寅
11=>巳
12=>坎
13=>未
14=>申
15=>乾
16=>坤
17=>离
18=>艮
第三步:根据环路与新序,进行矩阵缩减
分析的矩阵为:
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震 | 亥 | 卯 | 戌 | 辰+兑 | 酉 | 巽 | 子 | 丑 | 午 | 寅 | 巳 | 坎 | 未 | 申 | 乾 | 坤 | 离 | 艮 |
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| 亥 |
震、 |
| 辰+兑 |
亥、卯、戌、辰+兑、 |
| 酉 |
亥、辰+兑、 |
| 巽 |
酉、 |
| 子 |
震、巽、 |
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震、 |
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戌、辰+兑、酉、 |
| 寅 |
午、 |
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戌、 |
| 未 |
酉、丑、坎、 |
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戌、 |
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坎、 |
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卯、 |
| 艮 |
辰+兑、 |
第四步:对无环矩阵进行缩边,也就是去掉所有的向前边!
可达矩阵:
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震 | 亥 | 卯 | 戌 | 辰+兑 | 酉 | 巽 | 子 | 丑 | 午 | 寅 | 巳 | 坎 | 未 | 申 | 乾 | 坤 | 离 | 艮 |
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骨架矩阵
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震 | 亥 | 卯 | 戌 | 辰+兑 | 酉 | 巽 | 子 | 丑 | 午 | 寅 | 巳 | 坎 | 未 | 申 | 乾 | 坤 | 离 | 艮 |
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| 亥 |
震、 |
| 辰+兑 |
亥、卯、戌、 |
| 酉 |
辰+兑、 |
| 巽 |
酉、 |
| 子 |
巽、 |
| 丑 |
震、 |
| 午 |
酉、 |
| 寅 |
午、 |
| 坎 |
戌、 |
| 未 |
酉、丑、坎、 |
| 申 |
戌、 |
| 乾 |
坎、 |
| 离 |
卯、 |
| 艮 |
辰+兑、 |
第五步:对一般性骨架矩阵进行层级分解,可以是原因优先,可以是结果优先
原因优先层级划分最终图形
结果优先层级划分最终图形
弹性势能最大,两端发散的的层级结果
弹性势能最小,中间靠拢的结果
第六步:对一般性骨架矩阵的中的活动要素进行分析
| 层级的序号 | 原因优先的方法-得到的各层级的要素 | 结果优先的方法-得到的各层级要素 | 共同有的要素 | 活动的要素 |
| 1 | 震 | 震,卯,戌,巳,坤 | 震 | 卯,戌,巳,坤 |
| 2 | 亥,卯,戌 | 亥,丑,坎,申,离 | 亥 | 卯,戌,丑,坎,申,离 |
| 3 | 辰+兑 | 辰+兑,乾 | 辰+兑 | 乾 |
| 4 | 酉 | 酉,艮 | 酉 | 艮 |
| 5 | 巽,丑,午,坎 | 巽,午,未 | 巽,午 | 丑,坎,未 |
| 6 | 子,寅,巳,未,申,乾,坤,离,艮 | 子,寅 | 子,寅 | 巳,未,申,乾,坤,离,艮 |
由上表计算得出活动的要素以及它们活动的层级:
| 要素的序号 | 要素的名称 | 要素的标题 | 开始层级 | 终止层级 |
| 2 | 卯 | 卯 | 1 | 2 |
| 3 | 戌 | 戌 | 1 | 2 |
| 11 | 巳 | 巳 | 1 | 6 |
| 16 | 坤 | 坤 | 1 | 6 |
| 8 | 丑 | 丑 | 2 | 5 |
| 12 | 坎 | 坎 | 2 | 5 |
| 14 | 申 | 申 | 2 | 6 |
| 17 | 离 | 离 | 2 | 6 |
| 15 | 乾 | 乾 | 3 | 6 |
| 18 | 艮 | 艮 | 4 | 6 |
| 13 | 未 | 未 | 5 | 6 |
找到活动要素,并在层级中移动这些活动要素找出最好的结果。活动的要素要注意本身有因果关系的
A、分层的结果一定要符合箭头一定向上
B、不能增加层级的数目
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