代数法求骨架矩阵
此处输入要素的个数：
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骨架矩阵：指的是系统里存在环路，在进行缩点处理的后，得到的缩点矩阵再把其所有的向前边全部删除。得到的矩阵叫骨架矩阵
如果原始矩阵不存在回路，原始矩阵就是个DAG图，骨架矩阵符合一个简单的代数公式。
DAG图求骨架矩阵的代数公式：S=R-(R-I)2-I
显示的是一个随机 12 * 12 的方阵
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辰 | 寅 | 丑 | 申 | 未 | 子 | 卯 | 巳 | 午 | 酉 | 亥 | 戌 |
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第二步，对新矩阵求可达矩阵，可达矩阵如下
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辰 | 寅 | 丑 | 申 | 未 | 子 | 卯 | 巳 | 午 | 酉 | 亥 | 戌 |
| 辰 |
1 |
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1 |
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| 辰 |
辰、 |
| 寅 |
辰、寅、 |
| 丑 |
辰、寅、丑、 |
| 申 |
申、 |
| 未 |
辰、寅、丑、申、未、 |
| 子 |
辰、寅、丑、申、未、子、 |
| 卯 |
辰、寅、丑、卯、 |
| 巳 |
巳、 |
| 午 |
辰、寅、丑、申、未、子、午、 |
| 酉 |
辰、寅、丑、申、未、酉、 |
| 亥 |
辰、寅、巳、亥、 |
| 戌 |
辰、寅、丑、巳、亥、戌、 |
第三步，单位矩阵
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辰 | 寅 | 丑 | 申 | 未 | 子 | 卯 | 巳 | 午 | 酉 | 亥 | 戌 |
| 辰 |
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| 辰 |
辰、 |
| 寅 |
寅、 |
| 丑 |
丑、 |
| 申 |
申、 |
| 未 |
未、 |
| 子 |
子、 |
| 卯 |
卯、 |
| 巳 |
巳、 |
| 午 |
午、 |
| 酉 |
酉、 |
| 亥 |
亥、 |
| 戌 |
戌、 |
第四步，可达矩阵减去单位矩阵后的矩阵
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辰 | 寅 | 丑 | 申 | 未 | 子 | 卯 | 巳 | 午 | 酉 | 亥 | 戌 |
| 辰 |
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| 寅 |
辰、 |
| 丑 |
辰、寅、 |
| 未 |
辰、寅、丑、申、 |
| 子 |
辰、寅、丑、申、未、 |
| 卯 |
辰、寅、丑、 |
| 午 |
辰、寅、丑、申、未、子、 |
| 酉 |
辰、寅、丑、申、未、 |
| 亥 |
辰、寅、巳、 |
| 戌 |
辰、寅、丑、巳、亥、 |
第五步，两个矩阵相乘
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辰 | 寅 | 丑 | 申 | 未 | 子 | 卯 | 巳 | 午 | 酉 | 亥 | 戌 |
| 辰 |
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| 丑 |
辰、 |
| 未 |
辰、寅、 |
| 子 |
辰、寅、丑、申、 |
| 卯 |
辰、寅、 |
| 午 |
辰、寅、丑、申、未、 |
| 酉 |
辰、寅、丑、申、 |
| 亥 |
辰、 |
| 戌 |
辰、寅、巳、 |
第六步，可达矩阵减去上面的矩阵
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辰 | 寅 | 丑 | 申 | 未 | 子 | 卯 | 巳 | 午 | 酉 | 亥 | 戌 |
| 辰 |
1 |
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| 寅 |
1 |
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| 辰 |
辰、 |
| 寅 |
辰、寅、 |
| 丑 |
寅、丑、 |
| 申 |
申、 |
| 未 |
丑、申、未、 |
| 子 |
未、子、 |
| 卯 |
丑、卯、 |
| 巳 |
巳、 |
| 午 |
子、午、 |
| 酉 |
未、酉、 |
| 亥 |
寅、巳、亥、 |
| 戌 |
丑、亥、戌、 |
第七步，再减去单位矩阵后就是骨架矩阵
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辰 | 寅 | 丑 | 申 | 未 | 子 | 卯 | 巳 | 午 | 酉 | 亥 | 戌 |
| 辰 |
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| 寅 |
辰、 |
| 丑 |
寅、 |
| 未 |
丑、申、 |
| 子 |
未、 |
| 卯 |
丑、 |
| 午 |
子、 |
| 酉 |
未、 |
| 亥 |
寅、巳、 |
| 戌 |
丑、亥、 |
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